# Linear Equations in Two Variables : Exercise 4.4 (Mathematics NCERT Class 9th) Q.1      Give the geometric representation of y = 3 as an equation.
(i) in one variable           (ii) in two variables
Sol.

(i) The representation of the solution on the  number when y = 3 is treated as an equation in one variable is as under (ii)  We know that y = 3 can be written as 0. x + y = 3 as a linear equation in variables x and y. Now all the values of x are permissible as 0. x is always 0. However, y must satisfy the  relation y = 3.
Hence , three  solution of the given equation are
x = 0, y = 3 ;      x = 2, y = 3   ;    x = - 2 , y = 3 Plotting the  points (0, 3) (2, 3) and  (–2, 3) and on joining them we get the graph AB as a line  parallel to x-axis at a distance of 3 units above it.

Q.2       Given the geometric representations of 2x + 9 = 0  as an equation.
(i)  in one  variable             (ii)  in two variables
Sol.

(i) The  representation of the solution on the number line 2x + 9 = 0 i.e., $x = -{9\over 2}$ is treated as an  equation in one variable is as under. (ii) We know  that 2x + 9 = 0 can be written as 2x + 0y + 9  = 0 as a linear equation in variables x and y. Now all the  values of x are  permissible  as 0. y is always 0. However, x must  satisfy the relation 2x + 9 = 0
i.e., $x = - {9\over 2}$.
Hence three solution of the  given  equation are  $x =- {9\over 2}$,y = 0 ; $x =- {9\over 2}$,y = 2 and $x = - {9\over 2}$,y =– 2.
Therefore  Plotting  the point $\left( { - {9 \over 2},0} \right),\left( { - {9 \over 2},2} \right)\,and\,\left( { - {9 \over 2}, - 2} \right)$and on  joining them we get the graph AB as a line  parallel to y-axis at a distance of ${{9 \over 2}}$ on the left of y-axis. • Anonymous

Nice

• Anonymous

Not much bad but the theory is not satisfactory for me

• Yasharth

I did not got exact answer so it is not use full for me

• Anonymous

Better

• Neetu chawla

Nice

• • superb

its really amazing. it helpful to me

• Thanxxx for ur
help

• Mahesh BABU

This site is my favourite site to study love you Gujarat dronestudy site

• Anonymous

thanks

• Hamza faridi

Very helpful site Dron study is the best in all All all

• Kritika

Thanks for help

• Thanks to understand me this sum

• Thanks to understand me this sum because tomorrow is my exam

• Thank u it helped me a lot

• Ujjwal

Thank you for such a nice explanation. Very beneficial. Got prepared as tomorrow is my exam.

• • Thanks it is helpful for me

• Nice one

• Ritu nagar

Nice one

• it helped me more

• Nikita daksh

so thanx

• Anonymous

This is really very helpful !!!thanks a lot !!!!!!

• Sakshi sahu

Thanks you

• Thank you so much

Thank you so much

• Kanchan

It helps me to some extent

• Kanchan

Thnk u it helps me at some extent

• Aarohi

Thnk u it helps me at some extent

• Anonymous

• Ashutosh Lamba

• Anonymous

very thanks full to you

• Very easy solution

• VERY NICE

• mukesh kumar

its nice..

• Esha Dahiya

You are doing a great job .
It helps me a lot
Thank you☺☺☺☺☺☺

• anand

wonderful teamwork for helping all the students

• RAJPUT

it was good and thank u for this

• Anonymus

it's a great help, keep it up but try to put on numbers on the lines of the graph for a better representation. otherwise, it's awesome and very intelligible. Thanks a lot!!!

• Anonymous

Very thanks for helping us

• It is a very helpful to me. Very nice

• Rajput

Thanks a lot for helping me for my exams

• Rajput

Thanks a lot

• Fine

• Anonymous

Helps in despaie

• Shweta tiwari

I am very thankfully to dronstudy

• Shweta tiwari

Very nice and interesting thanx

• harsh babu

thanks for this idea

• Anonymous

Very useful

• diljit

it is good but you must also have to explain that how the other values would be put in the equation

• Anonymous

• Good

• J.Ramasastry

Keep 4th chapter all exercise problems

• J.Ramasastry

Keep all exercise problems what are there in text book give reply

• J.Ramasastry

I want all exercise problems

• Anonymous

Verrry nice.It is very helpful for preparation.

• moazzam

very very thanks for dron study

• Anonymous

• Very nice

• Muskan

Nice

• Very very thanks

• Anonymous

well.....

• ishita

• Yes it is

• Anonymous

It's nice

• ISHIKA

big thanks for helping

• Yes thanks too

• Anonymous

Okay but not satisfied

• Geetansh Malik

Help me

• Yash chaudhary

Thank u for giving me this great knowledge .

• Amrutha

• This was perfectly awesome
Thank for help

• Anonymous

Good job

• Very nice this was osm

• Anonymous

Wow ! This was ossom

• Ronnie

very nice

• ushaparihar

Very nice and thanks for giving us the knowledge about mathematics. Once again I want to give u a very big thankful☺

• alshifa

Very nice and convincing explanation thanks for all of us

• alshifa

Very well and convincing explanation thanks for my help to solve this questions

• Anonymous

Thanx

• Pooja kumari

Very nice
Thanks so much dronstudy

• sawan saraswat

Very very thanx to dronstudy

• RISHAB GUDIGAR

very very thnx to dronstudy

• #Seth Rollins

Thnx for solutions

• #Seth Rollins

Thnx for solutions

• Anonymous

Very very thanks for these best explained solutions

• Anshika Raj

The solution was wonderful and well explained

• Anonymous

Very very thnx to dronstudy

 FREE CBSE Video Solutions & Chapter Video Lectures WatchNOW