Solve the following linear equations.
Q.1
Sol. Given,
Multiplying by 3x on both the sides, we get,
(8x - 3) = 2 X 3x
(8x - 3) = 6x
8x - 6x = 3
2x = 3
Q.2
Sol. Given,
Multiplying by (7 – 6x) on both the sides, we get,
9x = 15 (7 - 6x)
9x =105 -90x
9x +90x = 105
99x =105
Q.3
Sol. Given,
Multiplying by 9(z + 15) on both the sides, we get,
9z = 4 (z + 15)
9z = 4z +60
9z - 4z = 60
5z = 60
z=15
Q.4
Sol. Given,
Multiplying by 5(2 – 6y) on both the sides, we get,
5(3y + 4) = -2 (2 - 6y)
15y + 20 = -4 + 12y
15y - 12y = -4 -20
3y = -24
y = -8
Q.5
Sol. Given,
Multiplying by 3(y + 2) on both the sides, we get,
3 (7y + 4) = -4 (y + 2)
21y + 12 = -4y - 8
21y + 4y = -8-12
25y = -20
Q.6 The ages of Hari and Harry are in the ratio 5:7. Four years from now the ratio of their ages will be 3:4. Find their present ages.
Sol. Let the ages of Hari and Harry be 5x and 7x respectively.
After 4 years, the ages of Hari and Harry will be (5x + 4) and (7x + 4) respectively.
Given,
4(5x + 4) = 3(7x + 4)
20x +16 = 21x + 12
20 - 21x =12 - 16
-x = -4
x = 4
Therefore, age of Hari = 5x = 5 x 4 = 20
Age of Harry = 7x = 7 x 4 = 28
Thus, the present ages of Hari and Harry are 20 and 28 years respectively.
Q.7 The denominator of a rational number is greater than its numerator by 8. If the numerator is increased by 17 and the denominator is decreased by 1, the number obtained is . Find the rational number.
Sol. Let the numerator of a rational number be a. Thus, denominator will be a + 8.
Therefore, rational number will be
Given,
2 (a + 17) = 3 (a + 7)
2a + 34 = 3a + 21
2a - 3a = 21 - 34
-a = -13
a = 13
Thus, the required rational is
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