# Data Handling : Exercise 5.3 (Mathematics NCERT Class 8th)

**Q.1 List the outcomes you can see in these experiments.
**

**(a) Spinning a wheel**

**(b) Tossing two coins together**

**(a) For the experiment of spinning a wheel, the possible outcomes are A, B, C and D.**

*Sol.*(b) For the experiment of two coins together, the possible outcomes are HT, TH, HH and TT where H represents Head and T represents Tail of the coins.

**Q.2 When a die is thrown, list the outcomes of an event of getting
**

**(i) (a) a prime number (b) not a prime number.**

**(ii) (a) a number greater than 5 (b) a number not greater than 5.**

**On throwing a dice, the possible outcomes are 1, 2, 3, 4, 5, and 6.**

*Sol.*(i) (a) The outcomes of event getting a prime number are 2, 3 and 5.

(b) The outcomes of event not getting a prime number are 1, 4 and 6.

(ii) (a) The outcomes of event getting a number greater the 5 is 6.

(b) The outcomes of event not getting a number greater than 5 are 1, 2, 3, 4 and 5.

**Q.3 Find the.
**

**(a) Probability of the pointer stopping on D in (Question 1-(a))?**

**(b) Probability of getting an ace from a well shuffled deck of 52 playing cards?**

**(c) Probability of getting a red apple. (See figure below)**

**(a) On spinning wheel, there are total 5 possible outcomes A, A, B, C, and D.**

*Sol.*Here, the possibility of pointer stopping on D is 1.

Hence, the probability of the pointer stopping on D =

(b) A deck consists of total 52 cards and there are 4 ace cards in 1 deck of cards.

Hence, the probability of getting an ace from a deck =

(c) In the figure, there are total 7 apples, out which there are 4 red apples.

Hence, the probability of getting a red apple = Â

**Q.4 Numbers 1 to 10 are written on ten separate slips (one number on one slip), kept in a box and mixed well. One slip is chosen from the box without looking into it. What is the probability of .
**

**(i) getting a number 6?**

**(ii) getting a number less than 6?**

**(iii) getting a number greater than 6?**

**(iv) getting a 1-digit number?**

**(i) There are total 10 slips in the box, out of which 6 is written only on 1 slip.**

*Sol.*Hence, the probability of getting a number 6 =

(ii) There are total 10 slips in the box, out of which there are 5 slips 1, 2, 3, 4 and 5 having number less than 6.

Hence, the probability of getting a number less than 6 =

(iii) There are total 10 slips in the box, out of which there are 4 slips 7, 8, 9 and 10 having number greater than 6.

Hence, the probability of getting a number greater than 6 =

(iv) There are total 10 slips in the box, out of which there are 9 slips 1, 2, 3, 4, 5, 6, 7, 8 and 9 having single digit number.

Hence, the probability of getting a single digit number =

**Q.5 If you have a spinning wheel with 3 green sectors, 1 blue sector and 1 red sector, what is the probability of getting a green sector? What is the probability of getting a non blue sector?
**

**Here, total number of sectors = 3 + 1 + 1 = 5.**

*Sol.*Now, there are 3 green sectors out of total 5 sectors.

Hence, the probability of getting a green sector =

Now, there will total 4 non blue sectors as we have 3 green sectors and 1 red sector out of total 5 sectors.

Hence, the probability of getting a non blue sector =

**Q.6 Find the probabilities of the events given in Question 2.
**

**On throwing a dice, there are total 6 possible outcomes which are 1, 2, 3, 4, 5, and 6.**

*Sol.*(i) (a) There are 3 possible outcomes of event getting a prime number which are 2, 3 and 5.

Hence, probability of getting a prime number =

(b) There are 3 possible outcomes of event not getting a prime number which are 1, 4 and 6.

Hence, probability of not getting a prime number =

(ii) (a) There is only 1 possible outcome of event getting a number greater the 5 which is 6.

Hence, probability of getting a number greater than 5 =

(b) There are 5 possible outcomes of event not getting a number greater than 5 which are 1, 2, 3, 4 and 5.

Hence, probability of not getting a number greater than 5 =

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