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**Q.1 In which quadrant or on which axis do each of the points (–2, 4) , (3, –1), (–1, 0), (1, 2) and (–3, –5) lie ? Verify your answer by locating them on the ****Cartesian plane.**

**Sol. **

**(i)** In the point (–2, 4), abscissa is negative and ordinate is positive. So, it lies in the second quadrant.

**(ii)** In the point (3, –1), abscissa is positive and ordinate is negative. So, it lies in the fourth quadrant.

**(iii)** The point (–1,0) lies on the negative x-axis.

**(iv)** In the point (1,2) abscissa and ordinate are positive, so it lies in the first quadrant.

**(v)** In the point (–3, –5) abscissa and ordinate are negative. Therefore , it lies in the third quadrant.

Let us locate these points on the cartesian plane. Plot the points (–2, 4), (3, –1), (–1, 0), (1,2) and (–3, – 5) as shown.

These points are respectively represented by A, B, C ,D and E which clearly verify their location.

**Q.2 Plot the points (x,y) given in the following table on the plane choosing suitable units of distance on the axes. **

* Sol. *Draw X'OX and Y'OY as the coordinate axes and mark their point of intersection O as the origin (0, 0).

In order to plot the point (–2, 8), we take 2 units on OX' and then 8 units parallel to OY to obtain the point A (–2, 8).

Similarly, we plot the point B (–1, 7).

In order to plot (0, –1.25), we take 1.25 units below x-axis on the y-axis to obtain C(0, –1.25).

In order to plot (1, 3) we take 1 unit on OX and then 3 units parallel to OY to obtain the point D (1, 3).

In order to plot (3, –1), we take 3 units on OX and then move 1 unit parallel to OY' to obtain the point E (3, –1).

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